2. If this is a bug, is there a way to do what I was trying to do within the system?

3. If this is a bug that is going to be fixed, what will happen to my existing rolls?

That's all I guess.

In the meantime, I want to see what I can do with the die roller.

personwholives previously rolled 6d6ic[4,3] = (6, 5, 1, 6, 6, 1) = -2 - invert
personwholives previously rolled 6d6c[4,3] = (4 2 1 5 1 5) = 0 - standard

I think one of those is the right way to do this, maybe?
ETA: Nope, try again.
personwholives previously rolled 6d6ic[7,3] = (6, 6, 4, 1, 1, 3) = 3

ETA2: That's got it. If you want to roll all of your dice at once, you can use that formula, though you have to roll each pool separately. So you can do something like this:
personwholives previously rolled 3d6ic[7,3] = (1, 5, 5) = 1 (Discipline)
personwholives previously rolled 2d6ic[7,3] = (5, 4) = 0 (Exhaustion)
personwholives previously rolled 1d6ic[7,3] = (1) = 1 (Madness)
Then sum the results to get your total successes. After that, I can still click to expand them to determine what dominates any particular roll.

Sol, you broke it!

Well, more accurately, you fixed it. Did you provide me a substitute that works?

Thanks for the work you do, by the way. This isn't meant as a complaint, I just want to know how to make my rolls work now.

If I understood correctly, what you want to do is only have failures and no chance of success correct? If that is the case, leaving empty now works correctly. So yohanleafheart previously rolled 4d10c[,3] = (7, 3, 5, 7) = -1, counts 3 and lower as failure and nothing as success.

Kendall expects it to work the other way around, counting 3 or lower as success and nothing as failure.

Thanks for the info. This should be in the wiki or something.

The count success modifier changes the calculation from an straight sum to a counting. Every die rolled above A1, or the max value for the die if none given, counts as a success other rolls count as 0. If A2 is given any die equal or lower than that number is counted as a failure and removes 1 success. If you use the ic token, the count is inverted. Which means that the low numbers count as a success and the higher as a failure.

The count success modifier changes the calculation from an straight sum to a counting. Every die rolled above A1, or the max value for the die if none given, counts as a success other rolls count as 0. If A2 is given any die equal or lower than that number is counted as a failure and removes 1 success. If you use the ic token, the count is inverted, which means that every die rolled below A1 counts as a success, and every die rolled above A2 (if provided) counts as a failure.